House Median Value Rank of School District within 50 miles of Lexington School District 4
Based on ACS 2006-2010 data*
A total of 27 results found. Show Results on Map.
Rank | House Median Value ▼ | School District / Population |
1. | $498,500 | Fort Jackson Schools / 14,081 |
1. | $498,500 | Richland County School District 2 within Fort Jackson / 14,081 |
3. | $170,600 | Lexington School District 5 / 89,967 |
4. | $162,400 | Richland School District 2 / 116,263 |
5. | $145,600 | Lexington School District 1 / 111,856 |
6. | $125,200 | Richland School District 1 / 201,777 |
7. | $118,000 | Aiken County School District / 159,958 |
8. | $113,100 | Lexington School District 2 / 62,801 |
9. | $112,800 | Lexington School District 3 / 13,838 |
10. | $110,900 | Sumter School District 17 / 51,642 |
11. | $110,800 | Kershaw County School District / 60,166 |
12. | $102,300 | Newberry County School District / 37,197 |
13. | $101,600 | Edgefield County School District / 26,680 |
14. | $99,900 | Saluda County School District / 13,902 |
15. | $94,500 | Calhoun County School District / 15,212 |
16. | $91,500 | Fairfield County School District / 24,040 |
17. | $89,700 | Clarendon School District 1 / 9,313 |
18. | $88,300 | Sumter School District 2 / 54,959 |
19. | $86,700 | Orangeburg School District 5 / 51,769 |
20. | $84,400 | Bamberg School District 1 / 8,347 |
21. | $84,100 | Bamberg School District 2 / 7,792 |
22. | $78,800 | Orangeburg School District 3 / 20,285 |
23. | $72,300 | Orangeburg School District 4 / 20,421 |
24. | $70,600 | Lexington School District 4 / 16,954 |
25. | $70,300 | Barnwell School District 29 / 5,298 |
26. | $69,300 | Barnwell School District 45 / 11,715 |
27. | $60,500 | Barnwell School District 19 / 5,709 |
Please note that we only rank locations with 'House Median Value' data. The rank above might not be a complete list. Locations without 'House Median Value' data are not listed.
*ACS stands for U.S. Census American Community Survey. According to the U.S. Census, if the date is a range, you can interpret the data as an average of the period of time.