Local Data Search
A total of 40 results found. Show Results on Map.
| Rank | House Median Value ▼ | Census Tract / Population |
| 1. | $235,600 | WI113100500 / 3,793 |
| 2. | $197,000 | WI113100400 / 2,360 |
| 3. | $188,200 | WI007960600 / 2,193 |
| 4. | $176,000 | WI013970400 / 4,175 |
| 5. | $172,400 | WI005000100 / 3,854 |
| 6. | $169,200 | WI013970600 / 1,939 |
| 7. | $163,800 | WI129950200 / 1,820 |
| 8. | $162,100 | WI129950300 / 2,630 |
| 9. | $159,300 | WI031030100 / 5,967 |
| 10. | $157,800 | WI003950500 / 2,188 |
| 11. | $156,800 | WI031030300 / 5,422 |
| 12. | $156,600 | WI113100300 / 4,127 |
| 13. | $155,700 | WI005000200 / 3,979 |
| 14. | $154,000 | WI007960200 / 1,742 |
| 15. | $151,900 | WI007960400 / 4,768 |
| 16. | $151,400 | WI031030200 / 4,716 |
| 17. | $150,800 | WI129950600 / 4,551 |
| 18. | $150,400 | WI013970700 / 2,447 |
| 19. | $147,700 | WI095960100 / 3,900 |
| 20. | $147,600 | WI099970400 / 1,904 |
| 21. | $145,100 | WI005001002 / 5,410 |
| 22. | $138,300 | WI129950500 / 5,033 |
| 23. | $134,000 | WI005000800 / 4,988 |
| 24. | $132,500 | WI113100800 / 1,636 |
| 25. | $127,500 | WI005000300 / 4,210 |
| 26. | $124,700 | WI107960300 / 2,350 |
| 27. | $124,600 | WI005000500 / 4,551 |
| 28. | $124,300 | WI005000600 / 6,084 |
| 29. | $123,600 | WI003950300 / 2,495 |
| 30. | $123,500 | WI113940000 / 3,209 |
| 31. | $121,300 | WI129950100 / 1,967 |
| 32. | $117,400 | WI113100700 / 1,490 |
| 33. | $116,300 | WI005000400 / 6,002 |
| 34. | $115,200 | WI107960400 / 3,051 |
| 35. | $108,900 | WI107960500 / 3,707 |
| 36. | $105,300 | WI107960200 / 2,125 |
| 37. | $102,300 | WI107960100 / 3,622 |
| 38. | $100,100 | WI003950400 / 2,723 |
| 39. | $95,600 | WI003950700 / 2,258 |
| 40. | $71,800 | WI003950600 / 1,371 |
Please note that we only rank locations with 'House Median Value' data. The rank above might not be a complete list. Locations without 'House Median Value' data are not listed.
*ACS stands for U.S. Census American Community Survey. According to the U.S. Census, if the date is a range, you can interpret the data as an average of the period of time.